Solution
Solution
Solution steps
Solve separable ODE:
Popular Examples
x(3y^2-2)y^'(x)-y^3=0,y(1)=2y^2dy=xdx(dy)/(dx)=18sqrt(xy)tan^2(x)cos^2(y)dx=dy(dy}{dx}=\frac{-6)/4 x^5y^8
Frequently Asked Questions (FAQ)
What is the solution for y^'+y=0,y(1)=1 ?
The solution for y^'+y=0,y(1)=1 is y=e^{-t+1}