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Popular >

y^'= y/x+2x+1

Solution

y^{^{'}} = \frac{y}{x} + 2 x + 1

Solution

y = 2 x^{2} + x ln (x) + c_{1} x

Solution steps

y^{'} (x) = \frac{y}{x} + 2 x + 1

Solve linear ODE:

y = 2 x^{2} + x ln (x) + c_{1} x

y = 2 x^{2} + x ln (x) + c_{1} x

Popular Examples

derivative of f(x)= 1/2 x^8 derivative of

f (x) = \frac{1}{2} x^{8}

(\partial)/(\partial x)(ye^x+xe^y)

\frac{\partial}{\partial x} (y e^{x} + x e^{y})

derivative of sqrt(t)derivative of

t

slope of (1.5)(2.8)slope

(1.5) (2.8)

integral from 1 to 6 of (x^2+3)/(7x-x^2)

\int_{1}^{6} \frac{x ^{2} + 3}{7 x - x ^{2}} d x

Frequently Asked Questions (FAQ)

What is the solution for y^'= y/x+2x+1 ?
The solution for y^'= y/x+2x+1 is y=2x^2+xln(x)+c_{1}x