What is the solution for (dy)/(dx)-x^2y^2=x^2 ?

The solution for (dy)/(dx)-x^2y^2=x^2 is y=tan((x^3)/3+c_{1})

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(dy)/(dx)-x^2y^2=x^2

\frac{d y}{d x} - x^{2} y^{2} = x^{2}

y = tan (\frac{x ^{3}}{3} + c_{1})

Solution steps

\frac{d y}{d x} - x^{2} y^{2} = x^{2}

Solve separable ODE:

y = tan (\frac{x ^{3}}{3} + c_{1})

y = tan (\frac{x ^{3}}{3} + c_{1})

y^{^{'}} = \frac{sin ( x )}{y}

\frac{d y}{d t} - 6 y = 5

(1 + t^{2}) \cdot \frac{d y}{d t} = 1 + y^{2}

\frac{d y}{d x} = \frac{4 y + 1}{3 x - 2}

ln (x) \frac{d x}{d y} = \frac{x}{y}

What is the solution for (dy)/(dx)-x^2y^2=x^2 ?
The solution for (dy)/(dx)-x^2y^2=x^2 is y=tan((x^3)/3+c_{1})