What is the solution for (1+y^2)cos(x)dx-1xdy=0,y(0)= pi/4 ?

The solution for (1+y^2)cos(x)dx-1xdy=0,y(0)= pi/4 is y=tan(\Ci(x)+c_{1})

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(1+y^2)cos(x)dx-1xdy=0,y(0)= pi/4

(1 + y^{2}) cos (x) d x - 1 x d y = 0, y (0) = \frac{π}{4}

y = tan (Ci (x) + c_{1})

Solution steps

(1 + y^{2}) cos (x) d x - 1 x d y = 0

Solve separable ODE:

y = tan (Ci (x) + c_{1})

y = tan (Ci (x) + c_{1})

\frac{d y}{d x} = e^{x - y}, y (0) = ln (6)

x y + (10 x y + x) y^{^{'}} = 0

\frac{d y}{d t} = 9 t sin^{2} (y), y (- 2) = \frac{π}{4}

2 y^{^{'}} = e^{x - y}

x y d x - (x^{2} + 1) d y = 0

What is the solution for (1+y^2)cos(x)dx-1xdy=0,y(0)= pi/4 ?
The solution for (1+y^2)cos(x)dx-1xdy=0,y(0)= pi/4 is y=tan(\Ci(x)+c_{1})