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Popular >

(dy)/(dt)=1+y^2

Solution

\frac{d y}{d t} = 1 + y^{2}

Solution

y = tan (t + c_{1})

Solution steps

\frac{d y}{d t} = 1 + y^{2}

Solve separable ODE:

y = tan (t + c_{1})

y = tan (t + c_{1})

Popular Examples

dy+0.15(y-25)dx=0

d y + 0.15 (y - 25) d x = 0

x/(1+x^2)dx-y/(3+y^2)dy=0

\frac{x}{1 + x ^{2}} d x - \frac{y}{3 + y ^{2}} d y = 0

(3x+3)dy+(2y+5)dx=0

(3 x + 3) d y + (2 y + 5) d x = 0

(dx)/(dt)=3t^2(x^2+36)

\frac{d x}{d t} = 3 t^{2} (x^{2} + 36)

(dy)/(dx)=2(1+x)(1+y^2),y=0

\frac{d y}{d x} = 2 (1 + x) (1 + y^{2}), y = 0

Frequently Asked Questions (FAQ)

What is the solution for (dy)/(dt)=1+y^2 ?
The solution for (dy)/(dt)=1+y^2 is y=tan(t+c_{1})