What is the solution for (dy)/(dx)=ysin(3x)-3ye^{-3x} ?

The solution for (dy)/(dx)=ysin(3x)-3ye^{-3x} is y=e^{-1/3 cos(3x)+e^{-3x}+c_{1}}

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dy)/(dx)=ysin(3x)-3ye^{-3x}

\frac{d y}{d x} = y sin (3 x) - 3 y e^{- 3 x}

y = e^{- \frac{1}{3} c o s (3 x) + e^{- 3 x} + c_{1}}

Solution steps

\frac{d y}{d x} = y sin (3 x) - 3 y e^{- 3 x}

Solve separable ODE:

y = e^{- \frac{1}{3} c o s (3 x) + e^{- 3 x} + c_{1}}

y = e^{- \frac{1}{3} c o s (3 x) + e^{- 3 x} + c_{1}}

(x - 1) (\frac{d y}{d x}) = 4 - y^{2}

\frac{d y}{d x} = x + 4 x y

x 1 - y^{2} d x + y 1 - x^{2} d y = 0

\frac{d y}{d t} - t y = y

\frac{d}{d θ} (r (θ)) + r (θ) tan (θ) = tan (θ)

What is the solution for (dy)/(dx)=ysin(3x)-3ye^{-3x} ?
The solution for (dy)/(dx)=ysin(3x)-3ye^{-3x} is y=e^{-1/3 cos(3x)+e^{-3x}+c_{1}}