What is the solution for y=xy^'-1/y ?

The solution for y=xy^'-1/y is y=sqrt(-x^2c_{1)-1},y=-sqrt(-x^2c_{1)-1}

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y=xy^'-1/y

y = x y^{^{'}} - \frac{1}{y}

y = - x^{2} c_{1} - 1, y = - - x^{2} c_{1} - 1

Solution steps

y = x y^{'} (x) - \frac{1}{y}

Solve separable ODE:

y = - x^{2} c_{1} - 1, y = - - x^{2} c_{1} - 1

y = - x^{2} c_{1} - 1, y = - - x^{2} c_{1} - 1

y^{^{'}} = \frac{2 e ^{x}}{e ^{y}}

(y + 1) cos (x) d x - d y = 0

\frac{d}{d x} (x^{4} + y^{4}) = 4, x^{3} + 4 y^{3} y^{^{'}} = 0

3 (1 + q^{2}) \frac{d p}{d q} = 2 pq (p^{3} - 1)

\frac{( 3 x ^{2} + 1 )}{2 y - 3} = \frac{d y}{d x}

What is the solution for y=xy^'-1/y ?
The solution for y=xy^'-1/y is y=sqrt(-x^2c_{1)-1},y=-sqrt(-x^2c_{1)-1}