What is the solution for xy^2(dy)/(dx)=x+1 ?

The solution for xy^2(dy)/(dx)=x+1 is y=\sqrt[3]{3x+3ln(x)+c_{1}}

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xy^2(dy)/(dx)=x+1

x y^{2} \frac{d y}{d x} = x + 1

Solution steps

x y^{2} \frac{d y}{d x} = x + 1

Solve separable ODE:

\frac{d y}{d x} = \frac{( y - 1 )}{x ^{2} - 1}

\frac{d y}{d x} = 2 x y^{2} + 3 x^{2} y^{2}, y (0) = 5

(x - 1) y^{^{'}} = (4 - y^{2})

\frac{d y}{d x} = sin (x) tan (y)

\frac{d y}{d x} + 5 y = 50

What is the solution for xy^2(dy)/(dx)=x+1 ?
The solution for xy^2(dy)/(dx)=x+1 is y=\sqrt[3]{3x+3ln(x)+c_{1}}