What is the solution for (dy)/(dx)=(xe^{x^2+y}) ?

The solution for (dy)/(dx)=(xe^{x^2+y}) is y=-ln(-1/2 e^{x^2}-c_{1})

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(dy)/(dx)=(xe^{x^2+y})

\frac{d y}{d x} = (x e^{x^{2} + y})

y = - ln (- \frac{1}{2} e^{x^{2}} - c_{1})

Solution steps

\frac{d y}{d x} = (x e^{x^{2} + y})

Solve separable ODE:

y = - ln (- \frac{1}{2} e^{x^{2}} - c_{1})

y = - ln (- \frac{1}{2} e^{x^{2}} - c_{1})

y^{^{'}} = \frac{t + 1}{t y + t}

\frac{d y}{d x} sin (π x) = y cos (π x)

y^{^{'}} = \frac{x ^{2} y ^{2}}{1 + x}

y^{^{'}} = \frac{x ^{2}}{y ^{3}}

2 sin (x) - y^{2} \frac{d y}{d x} = 0, y (0) = 1

What is the solution for (dy)/(dx)=(xe^{x^2+y}) ?
The solution for (dy)/(dx)=(xe^{x^2+y}) is y=-ln(-1/2 e^{x^2}-c_{1})