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Popular >

x^'=-2x+x

Solution

x^{^{'}} = - 2 x + x

Solution

x = e^{- t + c_{1}}

Solution steps

x^{'} (t) = - 2 x + x

Solve separable ODE:

x = e^{- t + c_{1}}

x = e^{- t + c_{1}}

Popular Examples

(dy)/(dx)+x^3y=4x^3

\frac{d y}{d x} + x^{3} y = 4 x^{3}

(dv)/(dt)=9.8-0.196v

\frac{d v}{d t} = 9.8 - 0.196 v

y^'=((3x^2-1))/(3+2y)

y^{^{'}} = \frac{( 3 x ^{2} - 1 )}{3 + 2 y}

derivative of 2x^3+y^2=6

\frac{d}{d x} (2 x^{3} + y^{2}) = 6

4x-2y(dy)/(dx)=0

4 x - 2 y \frac{d y}{d x} = 0

Frequently Asked Questions (FAQ)

What is the solution for x^'=-2x+x ?
The solution for x^'=-2x+x is x=e^{-t+c_{1}}