What is the solution for ((dy)/(dx))/y =x^{x-1} ?

The solution for ((dy)/(dx))/y =x^{x-1} is y=e^{integral of x^{x-1}}

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((dy)/(dx))/y =x^{x-1}

\frac{\frac{d y}{d x}}{y} = x^{x - 1}

y = e^{\int x^{x - 1} d x}

Solution steps

\frac{\frac{d y}{d x}}{y} = x^{x - 1}

Solve separable ODE:

y = e^{\int x^{x - 1} d x}

y = e^{\int x^{x - 1} d x}

y^{^{'}} + 2 y = 2, 6 sin (3 t) y (0) = 3

3 x \frac{d y}{d x} + 9 x^{3} y = 3 x^{3}

x \frac{d y}{d x} + cot (y) = 0

N^{^{'}} = r - a (N - b)^{2}

y^{^{'}} = \frac{1}{2} y cos^{2} (y)

What is the solution for ((dy)/(dx))/y =x^{x-1} ?
The solution for ((dy)/(dx))/y =x^{x-1} is y=e^{integral of x^{x-1}}