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Popular >

yy^'+6x=0,y(0)=4

Solution

y y^{^{'}} + 6 x = 0, y (0) = 4

Solution

y = - 6 x^{2} + 16

Solution steps

y y^{'} (x) + 6 x = 0

Solve separable ODE:

y = - 6 x^{2} + 16

y = - 6 x^{2} + 16

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Frequently Asked Questions (FAQ)

What is the solution for yy^'+6x=0,y(0)=4 ?
The solution for yy^'+6x=0,y(0)=4 is y=sqrt(-6x^2+16)