What is the solution for 5(dv)/(dx)+2v=3 ?

The solution for 5(dv)/(dx)+2v=3 is v=-(e^{(-2x-c_{1})/5})/(2)+3/2

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5(dv)/(dx)+2v=3

5 \frac{d v}{d x} + 2 v = 3

v = - \frac{e ^{\frac{- 2 x - c _{1}}{5}}}{2} + \frac{3}{2}

Solution steps

5 \frac{d v}{d x} + 2 v = 3

Solve separable ODE:

v = - \frac{e ^{\frac{- 2 x - c _{1}}{5}}}{2} + \frac{3}{2}

v = - \frac{e ^{\frac{- 2 x - c _{1}}{5}}}{2} + \frac{3}{2}

y y^{^{'}} - 3 x^{2} - x = 0

e^{x} cos (y) d x + (1 + e^{x}) sin (y) d y = 0

y^{^{'}} = 6 (x y)^{2}

\frac{d y}{d x} = e^{x + y}, y (0) = 0

x (H (x) x)^{2} d x + x^{2} (H (x) x) (H (x) d x + x d H (x)) = 0

What is the solution for 5(dv)/(dx)+2v=3 ?
The solution for 5(dv)/(dx)+2v=3 is v=-(e^{(-2x-c_{1})/5})/(2)+3/2