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Popular >

y^'=e^{-y}(x^5)/7

Solution

y^{^{'}} = e^{- y} \frac{x ^{5}}{7}

Solution

y = ln (\frac{x ^{6}}{42} + c_{1})

Solution steps

y^{'} (x) = e^{- y} \frac{x ^{5}}{7}

Solve separable ODE:

y = ln (\frac{x ^{6}}{42} + c_{1})

y = ln (\frac{x ^{6}}{42} + c_{1})

Popular Examples

(dy)/(dx)=(2x)/((y+1))

\frac{d y}{d x} = \frac{2 x}{( y + 1 )}

(dy)/(dx)=xy^2sin(x^2)

\frac{d y}{d x} = x y^{2} sin (x^{2})

(dy)/(dx)=\sqrt[3]{2/9 y}

(dy)/(dx)+(y-1/y)x=0

\frac{d y}{d x} + (y - \frac{1}{y}) x = 0

(dy)/(dx)=-3/8 x^5y^8

\frac{d y}{d x} = - \frac{3}{8} x^{5} y^{8}

Frequently Asked Questions (FAQ)

What is the solution for y^'=e^{-y}(x^5)/7 ?
The solution for y^'=e^{-y}(x^5)/7 is y=ln((x^6)/(42)+c_{1})