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Popular >

y^'=8y-12

Solution

y^{^{'}} = 8 y - 12

Solution

y = \frac{e ^{8 t + c_{1}}}{2} + \frac{3}{2}

Solution steps

y^{'} (t) = 8 y - 12

Solve separable ODE:

y = \frac{e ^{8 t + c_{1}}}{2} + \frac{3}{2}

y = \frac{e ^{8 t + c_{1}}}{2} + \frac{3}{2}

Popular Examples

u^'=7e^{9x-\H(x)}

u^{^{'}} = 7 e^{9 x - H (x)}

y^'-2 y/(coth(2x))=(-2)/(coth(2x))

y^{^{'}} - 2 \frac{y}{coth ( 2 x )} = \frac{- 2}{coth ( 2 x )}

e^x(dy)/(dx)=y^2

e^{x} \frac{d y}{d x} = y^{2}

e^{y} d x - x^{2} d y = 0

(dy)/(dx)=(2x)/(-8y-8),y(0)=-8

\frac{d y}{d x} = \frac{2 x}{- 8 y - 8}, y (0) = - 8

Frequently Asked Questions (FAQ)

What is the solution for y^'=8y-12 ?
The solution for y^'=8y-12 is y=(e^{8t+c_{1}})/2+3/2