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Popular >

y^'=(x+4)/(y^2)

Solution

y^{^{'}} = \frac{x + 4}{y ^{2}}

Solution

Solution steps

y^{'} (x) = \frac{x + 4}{y ^{2}}

Solve separable ODE:

Popular Examples

y^'=(4xy)/(x^2+1)

y^{^{'}} = \frac{4 x y}{x ^{2} + 1}

xy^2y^'=x+x^3,y(1)=2

x y^{2} y^{^{'}} = x + x^{3}, y (1) = 2

(dy}{dx}=\frac{1+x)/y

\frac{d y}{d x} = \frac{1 + x}{y}

y^'=(sin(x))/y ,y(pi/2)=1

y^{^{'}} = \frac{sin ( x )}{y}, y (\frac{π}{2}) = 1

(1-cos(x))((dy)/(dx))=ysin(x)

(1 - cos (x)) (\frac{d y}{d x}) = y sin (x)

Frequently Asked Questions (FAQ)

What is the solution for y^'=(x+4)/(y^2) ?
The solution for y^'=(x+4)/(y^2) is y=\sqrt[3]{(3x^2)/2+12x+c_{1}}