en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'=6e^{2x-y}

Solution

y^{^{'}} = 6 e^{2 x - y}

Solution

y = ln (3 e^{2 x} + c_{1})

Solution steps

y^{'} (x) = 6 e^{2 x - y}

Solve separable ODE:

y = ln (3 e^{2 x} + c_{1})

y = ln (3 e^{2 x} + c_{1})

Popular Examples

(dx)/(dt)= 5/(xe^{t+8x)}

\frac{d x}{d t} = \frac{5}{x e ^{t + 8 x}}

(dv}{dp}=\frac{-v)/p

\frac{d v}{d p} = \frac{- v}{p}

(dy)/(dx)-0.2xy=0,y(1)=1

\frac{d y}{d x} - 0.2 x y = 0, y (1) = 1

(dy)/(dt)=0.125(y-3),y(0)=5

\frac{d y}{d t} = 0.125 (y - 3), y (0) = 5

\frac{d y}{d x} = 2 y - 6

Frequently Asked Questions (FAQ)

What is the solution for y^'=6e^{2x-y} ?
The solution for y^'=6e^{2x-y} is y=ln(3e^{2x}+c_{1})