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Popular >

7yy^'=x,y(7)=3

Solution

7 y y^{^{'}} = x, y (7) = 3

Solution

y = \frac{x ^{2}}{7} + 2

Solution steps

7 y y^{'} (x) = x

Solve separable ODE:

y = \frac{x ^{2}}{7} + 2

y = \frac{x ^{2}}{7} + 2

Popular Examples

y^'-x/(5y^4)=0,y(0)=2,y(2)=a

y^{^{'}} - \frac{x}{5 y ^{4}} = 0, y (0) = 2, y (2) = a

(dy)/(dx)=sqrt(y^2-25)

\frac{d y}{d x} = y^{2} - 25

(1+x^2)dy-sqrt(1-y^2)dx=0

(1 + x^{2}) d y - 1 - y^{2} d x = 0

(dy)/(dx)=14xsec(y)

\frac{d y}{d x} = 14 x sec (y)

y^'=-(x-3)/(36y-108),y(3)=4

y^{^{'}} = - \frac{x - 3}{36 y - 108}, y (3) = 4

Frequently Asked Questions (FAQ)

What is the solution for 7yy^'=x,y(7)=3 ?
The solution for 7yy^'=x,y(7)=3 is y=sqrt((x^2)/7+2)