What is the solution for (dy)/(dx)=(xy-4x+y-4)/(xy-6x-3y+18) ?

The solution for (dy)/(dx)=(xy-4x+y-4)/(xy-6x-3y+18) is y=-2\W(-1/(2e^{(x+c_{1)-4)/2}(x-3)^2})+4

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(dy)/(dx)=(xy-4x+y-4)/(xy-6x-3y+18)

\frac{d y}{d x} = \frac{x y - 4 x + y - 4}{x y - 6 x - 3 y + 18}

y = - 2 W (- \frac{1}{2 e ^{\frac{x + c _{1} - 4}{2}} ( x - 3 ) ^{2}}) + 4

Solution steps

\frac{d y}{d x} = \frac{x y - 4 x + y - 4}{x y - 6 x - 3 y + 18}

Solve separable ODE:

y = - 2 W (- \frac{1}{2 e ^{\frac{x + c _{1} - 4}{2}} ( x - 3 ) ^{2}}) + 4

y = - 2 W (- \frac{1}{2 e ^{\frac{x + c _{1} - 4}{2}} ( x - 3 ) ^{2}}) + 4

\frac{d y}{d x} = x^{2} (y - 2), y (0) = 4

y^{^{'}} = e^{- y}, y (0) = 0

\frac{d y}{d x} = \frac{2}{3} x 1 - 9 y^{2}, y (0) = 0

\frac{d v}{d t} = \frac{2}{9} v

\frac{d}{d x} (x + y) = 1

What is the solution for (dy)/(dx)=(xy-4x+y-4)/(xy-6x-3y+18) ?
The solution for (dy)/(dx)=(xy-4x+y-4)/(xy-6x-3y+18) is y=-2\W(-1/(2e^{(x+c_{1)-4)/2}(x-3)^2})+4