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Popular >

y^'-y=0,y(0)=2

Solution

y^{^{'}} - y = 0, y (0) = 2

Solution

y = 2 e^{t}

Solution steps

y^{'} (t) - y = 0

Solve separable ODE:

y = 2 e^{t}

y = 2 e^{t}

Popular Examples

(dy)/(dx)y=arctan(3)x^2

\frac{d y}{d x} y = arctan (3) x^{2}

(dy)/(dt)=0.04-y/((4320/7))

\frac{d y}{d t} = 0.04 - \frac{y}{( \frac{4320}{7} )}

y^'=(2xy-2x)/(x^2+3)

y^{^{'}} = \frac{2 x y - 2 x}{x ^{2} + 3}

7y^'-2y-80=6y^'

7 y^{^{'}} - 2 y - 80 = 6 y^{^{'}}

(x^2-2x^2)dx+xydy=0

(x^{2} - 2 x^{2}) d x + x y d y = 0

Frequently Asked Questions (FAQ)

What is the solution for y^'-y=0,y(0)=2 ?
The solution for y^'-y=0,y(0)=2 is y=2e^t