What is the solution for (dy)/(dx)-2y^2cos^2(x)=3x^2y^2 ?

The solution for (dy)/(dx)-2y^2cos^2(x)=3x^2y^2 is y=-2/(2x^3+2x+sin(2x)+c_{1)}

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(dy)/(dx)-2y^2cos^2(x)=3x^2y^2

\frac{d y}{d x} - 2 y^{2} cos^{2} (x) = 3 x^{2} y^{2}

y = - \frac{2}{2 x ^{3} + 2 x + sin ( 2 x ) + c _{1}}

Solution steps

\frac{d y}{d x} - 2 y^{2} cos^{2} (x) = 3 x^{2} y^{2}

Solve separable ODE:

y = - \frac{2}{2 x ^{3} + 2 x + sin ( 2 x ) + c _{1}}

y = - \frac{2}{2 x ^{3} + 2 x + sin ( 2 x ) + c _{1}}

\frac{d y}{d x} y = 3 x^{5} + 4 x^{2} + x^{2} + 1000

y^{^{'}} - 2 y^{^{'}} - 3 y = 0

x (y - 1) d x + (x + 1) d y = 0, x = 2

y^{^{'}} = \frac{e ^{- x} - e ^{x}}{3 + 4 y}, y (0) = 1

y^{2} - 1 - (2 y + x y) y^{^{'}} = 0

What is the solution for (dy)/(dx)-2y^2cos^2(x)=3x^2y^2 ?
The solution for (dy)/(dx)-2y^2cos^2(x)=3x^2y^2 is y=-2/(2x^3+2x+sin(2x)+c_{1)}