x^'=-x+1

الحلّ

x^{^{'}} = - x + 1

x = e^{- t - c_{1}} + 1

خطوات الحلّ

x^{'} (t) = - x + 1

Solve separable ODE:

x = e^{- t - c_{1}} + 1

x = e^{- t - c_{1}} + 1

4 y x \frac{d x}{d y} = x^{2} + 1

(x^{2} - 3) y^{^{'}} = x (y^{2} + 16), y (2) = 4

\frac{d y}{d x} = 3 y^{2} - y^{2} sin (x)

\frac{d y}{d x} = 3 x e^{3 x + y}

y e^{2 x} - (1 + e^{2 x}) \frac{d y}{d x} = 0