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Popular >

x^'=-x+1

Solution

x^{^{'}} = - x + 1

Solution

x = e^{- t - c_{1}} + 1

Solution steps

x^{'} (t) = - x + 1

Solve separable ODE:

x = e^{- t - c_{1}} + 1

x = e^{- t - c_{1}} + 1

Graph

Popular Examples

4yx(dx)/(dy)=x^2+1

4 y x \frac{d x}{d y} = x^{2} + 1

(x^2-3)y^'=x(y^2+16),y(2)=4

(x^{2} - 3) y^{^{'}} = x (y^{2} + 16), y (2) = 4

(dy)/(dx)=3y^2-y^2sin(x)

\frac{d y}{d x} = 3 y^{2} - y^{2} sin (x)

(dy)/(dx)=3xe^{3x+y}

\frac{d y}{d x} = 3 x e^{3 x + y}

ye^{2x}-(1+e^{2x})(dy)/(dx)=0

y e^{2 x} - (1 + e^{2 x}) \frac{d y}{d x} = 0

Frequently Asked Questions (FAQ)

What is the solution for x^'=-x+1 ?
The solution for x^'=-x+1 is x=e^{-t-c_{1}}+1