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Popular >

y^'= x/y ,y(0)=0

Solution

y^{^{'}} = \frac{x}{y}, y (0) = 0

Solution

y = x, y = - x

Solution steps

y^{'} (x) = \frac{x}{y}

Solve separable ODE:

y = x, y = - x

y = x, y = - x

Popular Examples

y^'=(7x^2-1)/(7+5y)

y^{^{'}} = \frac{7 x ^{2} - 1}{7 + 5 y}

y^'=(x(1+y^2))/(4y)

y^{^{'}} = \frac{x ( 1 + y ^{2} )}{4 y}

(dy)/(dx)y=(ln(x))^{ln(x)}

\frac{d y}{d x} y = (ln (x))^{l n (x)}

y^{^{'}} = \frac{5 x + 8}{y}

(dy)/(dx)=2xsqrt(36-y^2)

\frac{d y}{d x} = 2 x 36 - y^{2}

Frequently Asked Questions (FAQ)

What is the solution for y^'= x/y ,y(0)=0 ?
The solution for y^'= x/y ,y(0)=0 is y=x,y=-x