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Popular >

xy^'+2y=1

Solution

x y^{^{'}} + 2 y = 1

Solution

y = - \frac{c _{1}}{2 x ^{2}} + \frac{1}{2}

Solution steps

x y^{'} (x) + 2 y = 1

Solve separable ODE:

y = - \frac{c _{1}}{2 x ^{2}} + \frac{1}{2}

y = - \frac{c _{1}}{2 x ^{2}} + \frac{1}{2}

Popular Examples

x \cdot \frac{d x}{d y} = 4 y

(dy)/(dx)+2/x y=0

\frac{d y}{d x} + \frac{2}{x} y = 0

(dy)/(dx)=y+y/(xln(x)),y(e)=1

\frac{d y}{d x} = y + \frac{y}{x ln ( x )}, y (e) = 1

(dy)/(dx)=-xy,y(0)=1

\frac{d y}{d x} = - x y, y (0) = 1

y^'+y=u,y(0)=(-1)/2

y^{^{'}} + y = u, y (0) = \frac{- 1}{2}

Frequently Asked Questions (FAQ)

What is the solution for xy^'+2y=1 ?
The solution for xy^'+2y=1 is y=-(c_{1})/(2x^2)+1/2