What is the solution for (dy)/(dx)=-7/4 x^3y^3 ?

The solution for (dy)/(dx)=-7/4 x^3y^3 is y=sqrt(-8/(-7x^4+c_{1))},y=-sqrt(-8/(-7x^4+c_{1))}

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(dy)/(dx)=-7/4 x^3y^3

\frac{d y}{d x} = - \frac{7}{4} x^{3} y^{3}

y = - \frac{8}{- 7 x ^{4} + c _{1}}, y = - - \frac{8}{- 7 x ^{4} + c _{1}}

Solution steps

\frac{d y}{d x} = - \frac{7}{4} x^{3} y^{3}

Solve separable ODE:

y = - \frac{8}{- 7 x ^{4} + c _{1}}, y = - - \frac{8}{- 7 x ^{4} + c _{1}}

y = - \frac{8}{- 7 x ^{4} + c _{1}}, y = - - \frac{8}{- 7 x ^{4} + c _{1}}

x^{2} d y = (9 + y^{2}) d x

(1 - y^{2})^{\frac{1}{2}} d x - (1 - x^{2})^{\frac{1}{2}} d y = 0

\frac{d y}{d x} = y sin (3 x) - 3 y e^{- 3 x}, y (0) = 1

y^{^{'}} + y tan (x) = 0, y (0) = a cos (x)

x^{2} (x d y + y d x) = 8 x d y - 8 y d x

What is the solution for (dy)/(dx)=-7/4 x^3y^3 ?
The solution for (dy)/(dx)=-7/4 x^3y^3 is y=sqrt(-8/(-7x^4+c_{1))},y=-sqrt(-8/(-7x^4+c_{1))}