What is the solution for (2y+2)dy-(4x^3+6)dx=0 ?

The solution for (2y+2)dy-(4x^3+6)dx=0 is y=-1+sqrt(x^4+6x+c_{1)+1},y=-sqrt(x^4+6x+c_{1)+1}-1

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(2y+2)dy-(4x^3+6)dx=0

(2 y + 2) d y - (4 x^{3} + 6) d x = 0

y = - 1 + x^{4} + 6 x + c_{1} + 1, y = - x^{4} + 6 x + c_{1} + 1 - 1

Solution steps

(2 y + 2) d y - (4 x^{3} + 6) d x = 0

Solve separable ODE:

y = - 1 + x^{4} + 6 x + c_{1} + 1, y = - x^{4} + 6 x + c_{1} + 1 - 1

y = - 1 + x^{4} + 6 x + c_{1} + 1, y = - x^{4} + 6 x + c_{1} + 1 - 1

(2 + y) d x - (x - 1) d y = 0

\frac{y ^{^{'}}}{x} = y

(1 + x^{2}) y^{^{'}} + x e^{- y} = 0

x^{^{'}} = a x (1 - \frac{x}{c})

(x^{2} - 20 x + 75) y^{^{'}} = y

What is the solution for (2y+2)dy-(4x^3+6)dx=0 ?
The solution for (2y+2)dy-(4x^3+6)dx=0 is y=-1+sqrt(x^4+6x+c_{1)+1},y=-sqrt(x^4+6x+c_{1)+1}-1