What is the solution for 3y^4-1+12xy^3(dy)/(dx)=0 ?

The solution for 3y^4-1+12xy^3(dy)/(dx)=0 is y=\sqrt[4]{(c_{1}+x)/(3x)},y=-\sqrt[4]{(c_{1}+x)/(3x)}

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3y^4-1+12xy^3(dy)/(dx)=0

3 y^{4} - 1 + 12 x y^{3} \frac{d y}{d x} = 0

Solution steps

3 y^{4} - 1 + 12 x y^{3} \frac{d y}{d x} = 0

Solve separable ODE:

y^{^{'}} - 10 y^{^{'}} + 25 y = 0

\frac{d y}{d x} - 0.075 y = - 9000

y^{^{'}} = e^{y + t}

y \cdot \frac{d y}{d x} = x \cdot \frac{x - e ^{x}}{e ^{y^{2}}}

x^{2} y^{^{'}} + \frac{1}{x} y = \frac{2}{x} y^{- 3}

What is the solution for 3y^4-1+12xy^3(dy)/(dx)=0 ?
The solution for 3y^4-1+12xy^3(dy)/(dx)=0 is y=\sqrt[4]{(c_{1}+x)/(3x)},y=-\sqrt[4]{(c_{1}+x)/(3x)}