Solution
Solution
Solution steps
Solve separable ODE:
Popular Examples
e^yy^'=((ln(t))^2)/t ,y(1)=ln(2)(dy}{dx}=\frac{y(y+1))/xy^'-5y=0,y(0)=2(dy)/(dt)=y+1,y(0)=0(dx)/(dt)=125-x/(100),x=4000,t=0
Frequently Asked Questions (FAQ)
What is the solution for y^'+2y=-10 ?
The solution for y^'+2y=-10 is y=e^{-2t+c_{1}}-5