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Popular >

y^'+12y=1

Solution

y^{^{'}} + 12 y = 1

Solution

y = - \frac{e ^{- 12 t - c_{1}}}{12} + \frac{1}{12}

Solution steps

y^{'} (t) + 12 y = 1

Solve separable ODE:

y = - \frac{e ^{- 12 t - c_{1}}}{12} + \frac{1}{12}

y = - \frac{e ^{- 12 t - c_{1}}}{12} + \frac{1}{12}

Popular Examples

y^'=-(5y(2x+9)^2)

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cos(3y)dy+sin(2x)dx=0

cos (3 y) d y + sin (2 x) d x = 0

Frequently Asked Questions (FAQ)

What is the solution for y^'+12y=1 ?
The solution for y^'+12y=1 is y=-(e^{-12t-c_{1}})/(12)+1/12