What is the solution for (dx)/(dt)+x/(100)=100 ?

The solution for (dx)/(dt)+x/(100)=100 is x=-e^{(-t-c_{1})/(100)}+10000

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(dx)/(dt)+x/(100)=100

\frac{d x}{d t} + \frac{x}{100} = 100

x = - e^{\frac{- t - c _{1}}{100}} + 10000

Solution steps

\frac{d x}{d t} + \frac{x}{100} = 100

Solve separable ODE:

x = - e^{\frac{- t - c _{1}}{100}} + 10000

x = - e^{\frac{- t - c _{1}}{100}} + 10000

\frac{d y}{d x} = (2 x y)

\frac{d y}{d x} = e^{x} \cdot y^{3}

\frac{d y}{d x} = 1 + y^{2}, y (π) = 0

\frac{d y}{d x} y = x^{3} - \frac{1}{x} + \frac{3}{x ^{4}} + π

x y d x - d y = 0

What is the solution for (dx)/(dt)+x/(100)=100 ?
The solution for (dx)/(dt)+x/(100)=100 is x=-e^{(-t-c_{1})/(100)}+10000