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Popular >

(x-x^2)y^'=2y,y(2)=4

Solution

(x - x^{2}) y^{^{'}} = 2 y, y (2) = 4

Solution

y = \frac{x ^{2}}{( x - 1 ) ^{2}}

Solution steps

(x - x^{2}) y^{'} (x) = 2 y

Solve separable ODE:

y = \frac{x ^{2}}{( x - 1 ) ^{2}}

y = \frac{x ^{2}}{( x - 1 ) ^{2}}

Popular Examples

(dy)/(dx)=(y+1)*(x+1)*cos(x^2+2x)

\frac{d y}{d x} = (y + 1) \cdot (x + 1) \cdot cos (x^{2} + 2 x)

y^'=9*t*e^{-y},y(0)=3

y^{^{'}} = 9 \cdot t \cdot e^{- y}, y (0) = 3

y^'=csc(y)cos(x/2),y(3pi)=(3pi)/2

y^{^{'}} = csc (y) cos (\frac{x}{2}), y (3 π) = \frac{3 π}{2}

(dy)/(dx)tan(y)=x

\frac{d y}{d x} tan (y) = x

(dx)/(dy)=sqrt(yx),y(1)=7

\frac{d x}{d y} = y x, y (1) = 7

Frequently Asked Questions (FAQ)

What is the solution for (x-x^2)y^'=2y,y(2)=4 ?
The solution for (x-x^2)y^'=2y,y(2)=4 is y=(x^2)/((x-1)^2)