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Popular >

y^'tan(x)=yln(y)

Solution

y^{^{'}} tan (x) = y ln (y)

Solution

y = e^{c_{1} s i n (x)}

Solution steps

y^{'} (x) tan (x) = y ln (y)

Solve separable ODE:

y = e^{c_{1} s i n (x)}

y = e^{c_{1} s i n (x)}

Popular Examples

(dy)/(dt)=([3t^2+4t+2])/([2y-2]),y(0)=-1

\frac{d y}{d t} = \frac{[ 3 t ^{2} + 4 t + 2 ]}{[ 2 y - 2 ]}, y (0) = - 1

y^'=(8(1+x))/(xy)

y^{^{'}} = \frac{8 ( 1 + x )}{x y}

(1+e^x)(dy)/(dx)+(e^xy)=0

(1 + e^{x}) \frac{d y}{d x} + (e^{x} y) = 0

(dx)/(dy)=e^{x-y}

\frac{d x}{d y} = e^{x - y}

(dy)/(dx)=-y(x^2-3)

\frac{d y}{d x} = - y (x^{2} - 3)

Frequently Asked Questions (FAQ)

What is the solution for y^'tan(x)=yln(y) ?
The solution for y^'tan(x)=yln(y) is y=e^{c_{1}sin(x)}