What is the solution for (dy)/(dx)=(x^2-1)/(y^2-1),y(2)=2 ?

The solution for (dy)/(dx)=(x^2-1)/(y^2-1),y(2)=2 is y=x

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(dy)/(dx)=(x^2-1)/(y^2-1),y(2)=2

\frac{d y}{d x} = \frac{x ^{2} - 1}{y ^{2} - 1}, y (2) = 2

y = x

Solution steps

\frac{d y}{d x} = \frac{x ^{2} - 1}{y ^{2} - 1}

Solve separable ODE:

y = x

y = x

y^{^{'}} = 7 y, y (0) = 1

f (x) = x^{5} cos (x) f^{^{'}} (x)

q^{^{'}} + \frac{1}{50} q = 0.2, q (0) = 5

sin (x) sin (y) y^{^{'}} + cos (y) cos (x) = 0

3 x sin (x) d x + cos (y) d y = 0

What is the solution for (dy)/(dx)=(x^2-1)/(y^2-1),y(2)=2 ?
The solution for (dy)/(dx)=(x^2-1)/(y^2-1),y(2)=2 is y=x