en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

(2y^2+3y)dx+2xydy=0

Solution

(2 y^{2} + 3 y) d x + 2 x y d y = 0

Solution

y = \frac{c _{1}}{2 x} - \frac{3}{2}

Solution steps

(2 y^{2} + 3 y) d x + 2 x y d y = 0

Solve separable ODE:

y = \frac{c _{1}}{2 x} - \frac{3}{2}

y = \frac{c _{1}}{2 x} - \frac{3}{2}

Popular Examples

y^'=(cos(x))/(2y),y(0)=-1

y^{^{'}} = \frac{cos ( x )}{2 y}, y (0) = - 1

(x^3+5x^3y^4)dx+e^{x^4}y^3dy=0

(x^{3} + 5 x^{3} y^{4}) d x + e^{x^{4}} y^{3} d y = 0

(dy)/(dx)=-6/9 x^5y^9

\frac{d y}{d x} = - \frac{6}{9} x^{5} y^{9}

y^'=e^{x^2}sqrt(64-y^2)

y^{^{'}} = e^{x^{2}} 64 - y^{2}

y^'=(y^2)/(1+x^2)

y^{^{'}} = \frac{y ^{2}}{1 + x ^{2}}

Frequently Asked Questions (FAQ)

What is the solution for (2y^2+3y)dx+2xydy=0 ?
The solution for (2y^2+3y)dx+2xydy=0 is y=(c_{1})/(2x)-3/2