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Popular >

d/(dθ)(y(θ))+y(θ)=0

Solution

\frac{d}{d θ} (y (θ)) + y (θ) = 0

Solution

y (θ) = e^{- θ + c_{1}}

Solution steps

\frac{d}{d θ} (y (θ)) + y (θ) = 0

Solve separable ODE:

y (θ) = e^{- θ + c_{1}}

y (θ) = e^{- θ + c_{1}}

Popular Examples

y^'=-3y,y(0)=e^{-3t},y(0)=1

y^{^{'}} = - 3 y, y (0) = e^{- 3 t}, y (0) = 1

(dy)/(dx)+ln(x)y=3ln(x)

\frac{d y}{d x} + ln (x) y = 3 ln (x)

y^'=2y^{-2},y(0)=3

y^{^{'}} = 2 y^{- 2}, y (0) = 3

(y+2)dx+sqrt(25-x^2)dy=0

(y + 2) d x + 25 - x^{2} d y = 0

2x^2y+3xy^'-15y=0

2 x^{2} y + 3 x y^{^{'}} - 15 y = 0

Frequently Asked Questions (FAQ)

What is the solution for d/(dθ)(y(θ))+y(θ)=0 ?
The solution for d/(dθ)(y(θ))+y(θ)=0 is y(θ)=e^{-θ+c_{1}}