What is the solution for y^'=(cos(x)e^{sin(x)})/(2y) ?

The solution for y^'=(cos(x)e^{sin(x)})/(2y) is y=sqrt(e^{sin(x))+c_{1}},y=-sqrt(e^{sin(x))+c_{1}}

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y^'=(cos(x)e^{sin(x)})/(2y)

y^{^{'}} = \frac{cos ( x ) e ^{s i n (x)}}{2 y}

y = e^{s i n (x)} + c_{1}, y = - e^{s i n (x)} + c_{1}

Solution steps

y^{'} (x) = \frac{cos ( x ) e ^{s i n (x)}}{2 y}

Solve separable ODE:

y = e^{s i n (x)} + c_{1}, y = - e^{s i n (x)} + c_{1}

y = e^{s i n (x)} + c_{1}, y = - e^{s i n (x)} + c_{1}

\frac{d P}{d t} = 5 Pt, P (1) = 5

cos (y) (2 ln (x) - x^{3}) \frac{d y}{d x} = \frac{2}{x} - 3 x^{2}

\frac{d y}{d x} y = - arccot (\frac{6 x}{3})

\frac{d y}{d x} y = sin (2) x^{5}

\frac{d y}{d x} = - x y + \frac{4 x}{y}

What is the solution for y^'=(cos(x)e^{sin(x)})/(2y) ?
The solution for y^'=(cos(x)e^{sin(x)})/(2y) is y=sqrt(e^{sin(x))+c_{1}},y=-sqrt(e^{sin(x))+c_{1}}