What is the solution for yln(x)y^'=(((y+1))/(x^{(1/2))})^2 ?

The solution for yln(x)y^'=(((y+1))/(x^{(1/2))})^2 is y=-1/(\W(-\frac{1){c_{1}ln(x)})}-1

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yln(x)y^'=(((y+1))/(x^{(1/2))})^2

y ln (x) y^{^{'}} = (\frac{( y + 1 )}{x ^{(\frac{1}{2})}})^{2}

y = - \frac{1}{W ( - \frac{1}{c _{1} l n ( x )} )} - 1

Solution steps

y ln (x) y^{'} (x) = (\frac{( y + 1 )}{x ^{(\frac{1}{2})}})^{2}

Solve separable ODE:

y = - \frac{1}{W ( - \frac{1}{c _{1} l n ( x )} )} - 1

y = - \frac{1}{W ( - \frac{1}{c _{1} l n ( x )} )} - 1

\int e^{5 x} d x

\int 12 x^{5} d x

\frac{\partial}{\partial t} (- t e^{t} sin (x))

\int_{0}^{5} ∣ 2 x - 5 ∣ d x

\frac{d}{d x} (2 x + 6)

What is the solution for yln(x)y^'=(((y+1))/(x^{(1/2))})^2 ?
The solution for yln(x)y^'=(((y+1))/(x^{(1/2))})^2 is y=-1/(\W(-\frac{1){c_{1}ln(x)})}-1