What is the solution for (dy)/(dx)=9x^2y^2,y\ne 0 ?

The solution for (dy)/(dx)=9x^2y^2,y\ne 0 is y=-1/(3x^3+c_{1)}

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(dy)/(dx)=9x^2y^2,y\ne 0

\frac{d y}{d x} = 9 x^{2} y^{2}, y \neq = 0

y = - \frac{1}{3 x ^{3} + c _{1}}

Solution steps

\frac{d y}{d x} = 9 x^{2} y^{2}

Solve separable ODE:

y = - \frac{1}{3 x ^{3} + c _{1}}

y = - \frac{1}{3 x ^{3} + c _{1}}

t y^{^{'}} + 2 y = 0

x y^{^{'}} = 6 y (1 + x^{3})

x \frac{d y}{d x} = e^{5 y + x}, x > 0

2 x (\frac{d y}{d x}) = 1 + y^{2}

(x^{2} + 4) (\frac{d y}{d x}) + x y = 2 x

What is the solution for (dy)/(dx)=9x^2y^2,y\ne 0 ?
The solution for (dy)/(dx)=9x^2y^2,y\ne 0 is y=-1/(3x^3+c_{1)}