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Popular >

xy^'=y^2ln(x)

Solution

x y^{^{'}} = y^{2} ln (x)

Solution

y = - \frac{2}{ln ^{2} ( x ) + c _{1}}

Solution steps

x y^{'} (x) = y^{2} ln (x)

Solve separable ODE:

y = - \frac{2}{ln ^{2} ( x ) + c _{1}}

y = - \frac{2}{ln ^{2} ( x ) + c _{1}}

Popular Examples

(x^3y^3)dx-3xy^2dy=0

(x^{3} y^{3}) d x - 3 x y^{2} d y = 0

e^{x^2}(dy)/(dx)+2e^{x^2}xy=e^{x^2}x

e^{x^{2}} \frac{d y}{d x} + 2 e^{x^{2}} x y = e^{x^{2}} x

d y = \frac{8 y}{x} d x

y^'=(y-1)/(x+1)

y^{^{'}} = \frac{y - 1}{x + 1}

ydx-xdy=2dy,y(1)=1

y d x - x d y = 2 d y, y (1) = 1

Frequently Asked Questions (FAQ)

What is the solution for xy^'=y^2ln(x) ?
The solution for xy^'=y^2ln(x) is y=-2/(ln^2(x)+c_{1)}