en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

x^'=-5x,x(0)=1

Solution

x^{^{'}} = - 5 x, x (0) = 1

Solution

x = e^{- 5 t}

Solution steps

x^{'} (t) = - 5 x

Solve separable ODE:

x = e^{- 5 t}

x = e^{- 5 t}

Graph

Popular Examples

y^'(t)=(1-y)(3+y),y(0)=3

y^{^{'}} (t) = (1 - y) (3 + y), y (0) = 3

(sqrt(x)+x)*(dy)/(dx)=sqrt(y)+y

(x + x) \cdot \frac{d y}{d x} = y + y

y^{^{'}} = y (3 t - 30)

(dx)/(dt)=10-(70x)/(100)

\frac{d x}{d t} = 10 - \frac{70 x}{100}

y^{^{'}} = 12 x^{3} e^{y}

Frequently Asked Questions (FAQ)

What is the solution for x^'=-5x,x(0)=1 ?
The solution for x^'=-5x,x(0)=1 is x=e^{-5t}