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Popular >

(dV)/(dt)=kV(t)^2

Solution

\frac{d V}{d t} = kV (t)^{2}

Solution

V = e^{\frac{k t ^{3}}{3} + c_{1}}

Solution steps

\frac{d V}{d t} = kV t^{2}

Solve separable ODE:

V = e^{\frac{k t ^{3}}{3} + c_{1}}

V = e^{\frac{k t ^{3}}{3} + c_{1}}

Graph

Popular Examples

(dy)/(dx)=-(9/6)^2y^6

\frac{d y}{d x} = - (\frac{9}{6})^{2} y^{6}

(dy)/(dx)-(xy)/(1-x^2)=(xy^2)/(1-x^2)

\frac{d y}{d x} - \frac{x y}{1 - x ^{2}} = \frac{x y ^{2}}{1 - x ^{2}}

ye^x(dy)/(dx)=e^{-y}+e^{-2x-y}

y e^{x} \frac{d y}{d x} = e^{- y} + e^{- 2 x - y}

x(dy)/(dx)=y^2-9

x \frac{d y}{d x} = y^{2} - 9

x^{3} y^{^{'}} = 1 + y

Frequently Asked Questions (FAQ)

What is the solution for (dV)/(dt)=kV(t)^2 ?
The solution for (dV)/(dt)=kV(t)^2 is V=e^{(kt^3)/3+c_{1}}