What is the solution for y^'=x^2*y-1.1*y ?

The solution for y^'=x^2*y-1.1*y is y=e^{0.33333…x^3-1.1x+c_{1}}

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y^'=x^2y-1.1y

y^{^{'}} = x^{2} \cdot y - 1.1 \cdot y

y = e^{0.33333 \dots x^{3} - 1.1 x + c_{1}}

Solution steps

y^{'} (x) = x^{2} \cdot y - 1.1 \cdot y

Solve separable ODE:

y = e^{0.33333 \dots x^{3} - 1.1 x + c_{1}}

y = e^{0.33333 \dots x^{3} - 1.1 x + c_{1}}

y^{^{'}} = \frac{3 t ^{2}}{4 + 2 y}, y (0) = - 1

y^{^{'}} = 4 y^{3}

\frac{d y}{d x} = (x^{5} (y - 6)), y (0) = 8

y x^{2} d x - 3 y d x = d y

\frac{d y}{d t} = \frac{t}{t ^{2} y + y}, y (0) = 4

What is the solution for y^'=x^2*y-1.1*y ?
The solution for y^'=x^2*y-1.1*y is y=e^{0.33333…x^3-1.1x+c_{1}}