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Popular >

(x^3+1)y^'=x^2y

Solution

(x^{3} + 1) y^{^{'}} = x^{2} y

Solution

Solution steps

(x^{3} + 1) y^{'} (x) = x^{2} y

Solve separable ODE:

Popular Examples

y^2(x+1)+2xyy^'=0

y^{2} (x + 1) + 2 x y y^{^{'}} = 0

(t^2-16t+55)*(dy)/(dt)=y

(t^{2} - 16 t + 55) \cdot \frac{d y}{d t} = y

(dy)/(dx)=e^{-x-y-2}

\frac{d y}{d x} = e^{- x - y - 2}

(dy)/(dx)= y/((x+1)sqrt(x))

\frac{d y}{d x} = \frac{y}{( x + 1 ) x}

y \frac{d y}{d x} = x^{2}

Frequently Asked Questions (FAQ)

What is the solution for (x^3+1)y^'=x^2y ?
The solution for (x^3+1)y^'=x^2y is y=c_{1}\sqrt[3]{x^3+1}