en

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^'+0.2ty=6t

Solution

y^{^{'}} + 0.2 t y = 6 t

Solution

y = 5 e^{c_{1} - \frac{t ^{2}}{10}} + 30

Solution steps

y^{'} (t) + 0.2 t y = 6 t

Solve separable ODE:

y = 5 e^{c_{1} - \frac{t ^{2}}{10}} + 30

y = 5 e^{c_{1} - \frac{t ^{2}}{10}} + 30

Popular Examples

y^{^{'}} = 7 y - 8

5x-5xcos(y)dx+xsin(y)dy=0

5 x - 5 x cos (y) d x + x sin (y) d y = 0

(dy)/(dx)=x^2y-3y+x^2-3

\frac{d y}{d x} = x^{2} y - 3 y + x^{2} - 3

(dy)/(dx)=(-0.8)/(cos(y)),y(0)= pi/3

\frac{d y}{d x} = \frac{- 0.8}{cos ( y )}, y (0) = \frac{π}{3}

(sin(x))/(1+y)(dy)/(dx)=cos(x)

\frac{sin ( x )}{1 + y} \frac{d y}{d x} = cos (x)

Frequently Asked Questions (FAQ)

What is the solution for y^'+0.2ty=6t ?
The solution for y^'+0.2ty=6t is y=5e^{c_{1}-(t^2)/(10)}+30