What is the solution for 4xy^2dx+(x^2+1)dy=0 ?

The solution for 4xy^2dx+(x^2+1)dy=0 is y=-1/(-2ln(x^2+1)+c_{1)}

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4xy^2dx+(x^2+1)dy=0

4 x y^{2} d x + (x^{2} + 1) d y = 0

y = - \frac{1}{- 2 ln ( x ^{2} + 1 ) + c _{1}}

Solution steps

4 x y^{2} d x + (x^{2} + 1) d y = 0

Solve separable ODE:

y = - \frac{1}{- 2 ln ( x ^{2} + 1 ) + c _{1}}

y = - \frac{1}{- 2 ln ( x ^{2} + 1 ) + c _{1}}

\frac{d y}{d x} = - \frac{6}{8} x^{4} y^{6}

tan (x) sin^{2} (y) d x + cos^{2} (x) cos (y) d y = 0

\frac{d y}{d x} = \frac{4 x}{7 y}

\frac{d y}{d x} = - \frac{4}{5} x^{3} y^{8}

2 y (y - 1) d x + x (2 y - 1) d y = 0

What is the solution for 4xy^2dx+(x^2+1)dy=0 ?
The solution for 4xy^2dx+(x^2+1)dy=0 is y=-1/(-2ln(x^2+1)+c_{1)}