What is (\partial)/(\partial m)(1/2 mv^2) ?

The answer to (\partial)/(\partial m)(1/2 mv^2) is (v^2)/2

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(\partial)/(\partial m)(1/2 mv^2)

\frac{\partial}{\partial m} (\frac{1}{2} m v^{2})

\frac{v ^{2}}{2}

Solution steps

\frac{\partial}{\partial m} (\frac{1}{2} m v^{2})

Treat

v

as a constant

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= \frac{1}{2} v^{2} \frac{\partial}{\partial m} (m)

Apply the common derivative:

\frac{\partial}{\partial m} (m) = 1

= \frac{1}{2} v^{2} \cdot 1

Simplify

\frac{1}{2} v^{2} \cdot 1 : \frac{v ^{2}}{2}

= \frac{v ^{2}}{2}

y^{^{''}} + 8.2176 + 207.36 y = 0, y (0) = 0, y^{^{'}} (0) = - 10

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What is (\partial)/(\partial m)(1/2 mv^2) ?
The answer to (\partial)/(\partial m)(1/2 mv^2) is (v^2)/2