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Popular >

y^'sec(x)=5y^2

Solution

y^{^{'}} sec (x) = 5 y^{2}

Solution

y = - \frac{1}{5 sin ( x ) + c _{1}}

Solution steps

y^{'} (x) sec (x) = 5 y^{2}

Solve separable ODE:

y = - \frac{1}{5 sin ( x ) + c _{1}}

y = - \frac{1}{5 sin ( x ) + c _{1}}

Graph

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Frequently Asked Questions (FAQ)

What is the solution for y^'sec(x)=5y^2 ?
The solution for y^'sec(x)=5y^2 is y=-1/(5sin(x)+c_{1)}