What is the solution for y^'+a*y^2=-b ?

The solution for y^'+a*y^2=-b is y=(sqrt(b)tan(-sqrt(a)sqrt(b)t-c_{1}sqrt(a)sqrt(b)))/(sqrt(a))

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y^'+a*y^2=-b

y^{^{'}} + a \cdot y^{2} = - b

y = \frac{b tan ( - a b t - c _{1} a b )}{a}

Solution steps

y^{'} (t) + a \cdot y^{2} = - b

Solve separable ODE:

y = \frac{b tan ( - a b t - c _{1} a b )}{a}

y = \frac{b tan ( - a b t - c _{1} a b )}{a}

f^{^{'}} (t) = f (t)^{- 1}

y^{^{'}} = 2 x^{3} (1 + y^{2}), y (1) = 0

\frac{d x}{d t} = 8 (x^{2} + 1), x (\frac{π}{4}) = 1

\frac{d h}{d t} = - 0.03 h - 19

\frac{d y}{d x} = 8 (2 - y)

What is the solution for y^'+a*y^2=-b ?
The solution for y^'+a*y^2=-b is y=(sqrt(b)tan(-sqrt(a)sqrt(b)t-c_{1}sqrt(a)sqrt(b)))/(sqrt(a))