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Popular >

y^'=y*e^{-x}

Solution

y^{^{'}} = y \cdot e^{- x}

Solution

y = e^{- e^{- x} + c_{1}}

Solution steps

y^{'} (x) = y \cdot e^{- x}

Solve separable ODE:

y = e^{- e^{- x} + c_{1}}

y = e^{- e^{- x} + c_{1}}

Graph

Popular Examples

(dy)/(dx)=6x^2+6x^2y^2

\frac{d y}{d x} = 6 x^{2} + 6 x^{2} y^{2}

(dy)/(dx)=((ln(x))^6)/(xy^2)

\frac{d y}{d x} = \frac{( ln ( x ) ) ^{6}}{x y ^{2}}

(e^y-1)(dy)/(dx)=2+cos(x)

(e^{y} - 1) \frac{d y}{d x} = 2 + cos (x)

y^{^{'}} + 5 y^{3} = 0

(dy)/(dx)=(x^2+1)/(y^2+1),y(2)=2

\frac{d y}{d x} = \frac{x ^{2} + 1}{y ^{2} + 1}, y (2) = 2

Frequently Asked Questions (FAQ)

What is the solution for y^'=y*e^{-x} ?
The solution for y^'=y*e^{-x} is y=e^{-e^{-x}+c_{1}}