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(dy)/(dx)=(35)/(y^{1/6)+49x^2y^{1/6}}(dy)/(dx)y=-6x^{3/2}(dy)/(dx)=((1+y^2)/(1+x^2))(dy)/(dx)=(2y^2)/(sqrt(x)),y(9)= 1/49sin(2x)dx+cos(3y)dy=0,y(pi/2)=(pi/3)
Frequently Asked Questions (FAQ)
What is the y'(t)=y(y+1)^2,y(0)=1 ?
The y'(t)=y(y+1)^2,y(0)=1 is 4